Integrand size = 16, antiderivative size = 90 \[ \int \frac {1}{\sqrt {3-6 x^2+2 x^4}} \, dx=\frac {\left (3+\sqrt {6} x^2\right ) \sqrt {\frac {3-6 x^2+2 x^4}{\left (3+\sqrt {6} x^2\right )^2}} \operatorname {EllipticF}\left (2 \arctan \left (\sqrt [4]{\frac {2}{3}} x\right ),\frac {1}{4} \left (2+\sqrt {6}\right )\right )}{2 \sqrt [4]{6} \sqrt {3-6 x^2+2 x^4}} \]
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Time = 0.01 (sec) , antiderivative size = 90, normalized size of antiderivative = 1.00, number of steps used = 1, number of rules used = 1, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.062, Rules used = {1110} \[ \int \frac {1}{\sqrt {3-6 x^2+2 x^4}} \, dx=\frac {\left (\sqrt {6} x^2+3\right ) \sqrt {\frac {2 x^4-6 x^2+3}{\left (\sqrt {6} x^2+3\right )^2}} \operatorname {EllipticF}\left (2 \arctan \left (\sqrt [4]{\frac {2}{3}} x\right ),\frac {1}{4} \left (2+\sqrt {6}\right )\right )}{2 \sqrt [4]{6} \sqrt {2 x^4-6 x^2+3}} \]
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Rule 1110
Rubi steps \begin{align*} \text {integral}& = \frac {\left (3+\sqrt {6} x^2\right ) \sqrt {\frac {3-6 x^2+2 x^4}{\left (3+\sqrt {6} x^2\right )^2}} F\left (2 \tan ^{-1}\left (\sqrt [4]{\frac {2}{3}} x\right )|\frac {1}{4} \left (2+\sqrt {6}\right )\right )}{2 \sqrt [4]{6} \sqrt {3-6 x^2+2 x^4}} \\ \end{align*}
Time = 10.07 (sec) , antiderivative size = 81, normalized size of antiderivative = 0.90 \[ \int \frac {1}{\sqrt {3-6 x^2+2 x^4}} \, dx=\frac {\sqrt {3-\sqrt {3}-2 x^2} \sqrt {3+\left (-3+\sqrt {3}\right ) x^2} \operatorname {EllipticF}\left (\arcsin \left (\sqrt {1+\frac {1}{\sqrt {3}}} x\right ),2-\sqrt {3}\right )}{\sqrt {6} \sqrt {3-6 x^2+2 x^4}} \]
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Time = 0.62 (sec) , antiderivative size = 82, normalized size of antiderivative = 0.91
method | result | size |
default | \(\frac {3 \sqrt {1-\left (1+\frac {\sqrt {3}}{3}\right ) x^{2}}\, \sqrt {1-\left (1-\frac {\sqrt {3}}{3}\right ) x^{2}}\, F\left (\frac {x \sqrt {9+3 \sqrt {3}}}{3}, \frac {\sqrt {6}}{2}-\frac {\sqrt {2}}{2}\right )}{\sqrt {9+3 \sqrt {3}}\, \sqrt {2 x^{4}-6 x^{2}+3}}\) | \(82\) |
elliptic | \(\frac {3 \sqrt {1-\left (1+\frac {\sqrt {3}}{3}\right ) x^{2}}\, \sqrt {1-\left (1-\frac {\sqrt {3}}{3}\right ) x^{2}}\, F\left (\frac {x \sqrt {9+3 \sqrt {3}}}{3}, \frac {\sqrt {6}}{2}-\frac {\sqrt {2}}{2}\right )}{\sqrt {9+3 \sqrt {3}}\, \sqrt {2 x^{4}-6 x^{2}+3}}\) | \(82\) |
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none
Time = 0.07 (sec) , antiderivative size = 36, normalized size of antiderivative = 0.40 \[ \int \frac {1}{\sqrt {3-6 x^2+2 x^4}} \, dx=-\frac {1}{6} \, \sqrt {\sqrt {3} + 3} {\left (\sqrt {3} - 3\right )} F(\arcsin \left (\frac {1}{3} \, \sqrt {3} x \sqrt {\sqrt {3} + 3}\right )\,|\,-\sqrt {3} + 2) \]
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\[ \int \frac {1}{\sqrt {3-6 x^2+2 x^4}} \, dx=\int \frac {1}{\sqrt {2 x^{4} - 6 x^{2} + 3}}\, dx \]
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\[ \int \frac {1}{\sqrt {3-6 x^2+2 x^4}} \, dx=\int { \frac {1}{\sqrt {2 \, x^{4} - 6 \, x^{2} + 3}} \,d x } \]
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\[ \int \frac {1}{\sqrt {3-6 x^2+2 x^4}} \, dx=\int { \frac {1}{\sqrt {2 \, x^{4} - 6 \, x^{2} + 3}} \,d x } \]
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Timed out. \[ \int \frac {1}{\sqrt {3-6 x^2+2 x^4}} \, dx=\int \frac {1}{\sqrt {2\,x^4-6\,x^2+3}} \,d x \]
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